Chemical EquilibriumHard

Question

The two equilibria AB$\rightleftharpoons$A+ + B– and AB + B– $\rightleftharpoons$AB2− are simultaneously maintained in a solution with equilibrium constants K1 and K2, respectively. The ratio of A+ to AB2− in the solution is

Options

A.directly proportional to the concentration of B.
B.inversely proportional to the concentration of B.
C.directly proportional to the square of the concentration of B.
D.inversely proportional to the square of the concentration of B.

Solution

$K_{1} = \frac{\left\lbrack A^{+} \right\rbrack\left\lbrack B^{-} \right\rbrack}{\lbrack AB\rbrack}\text{ and }K_{2} = \frac{\left\lbrack AB_{2}^{-} \right\rbrack}{\lbrack AB\rbrack\left\lbrack B^{-} \right\rbrack}$

Now, $\frac{\left\lbrack A^{+} \right\rbrack}{\left\lbrack AB_{2}^{-} \right\rbrack} = \frac{K_{1}}{K_{2}}.\left\lbrack B^{-} \right\rbrack^{2}$

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