Chemical EquilibriumHard
Question
The equilibrium constant for the reaction: H3BO3 + Glycerin$\rightleftharpoons$ (H3BO3 + Glycerin complex) is 0.90. How much glycerin should be added to 1 L of 0.10 M-H3BO3 solution, so that 60% of the H3BO3 is converted to boric acid–glycerin complex?
Options
A.Infinite
B.1.73 M
C.0.10 M
D.2.27 M
Solution
H3BO3 + Glycerin $\rightleftharpoons$ Complex
Initial concert 0.1 a M 0
Equ. Concert 0.1 – 0.06 (a – 0.06) M 0.06 M
= 0.04 M
Now, $K_{eq} = 0.9 = \frac{0.06}{(0.04) \times (a - 0.06)} \Rightarrow a = 1.73\text{ M}$
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
Equilibrium constant for the following equilibrium is given at 0ºC.Na2HPO4 . 12H2O (s) ⇋ Na2HPO4 . 7H2O (s) + 5H2O...If for the equilibria NH2COONH4(s) $\rightleftharpoons$N2 + H2 + CO + O2, the value of KP at 800 K is 27 × 2λ/2 and the ...Listed in the table are forward and reverse rate constant for the reaction 2NO(g) ⇋ N2(g) + O2(g) Select the corre...The following equilibria are given : N2 + 3H2 ⇋ 2NH3 K1 N2 + O2 ⇋ 2NO K2 H2 + O2 ⇋ H2O K3 The equilibr...An aqueous solution of volume 500 ml, when the reaction 2Ag+ (aq) + Cu(s) $\rightleftharpoons$Cu2+ (aq) + 2Ag(s) reached...