Chemical EquilibriumHard

Question

In a system A(s) $\rightleftharpoons$2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor of 2, then it will cause the equilibrium concentration of B to decrease by

Options

A.two times the original value
B.one half of its original value
C.$2\sqrt{2}$times its original value
D.8 times its original value

Solution

K = [B]2 [C]3 = Constant

Now, $\lbrack B\rbrack^{2}\lbrack C\rbrack^{3} = \lbrack B\rbrack_{new}^{2} \times \left( 2\lbrack C\rbrack \right)^{3} \Rightarrow \lbrack B\rbrack_{new} = \frac{\lbrack B\rbrack}{2\sqrt{2}}$

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

The value of KP for the equilibrium NH4HS(s) $\rightleftharpoons$NH3(g) + H2S(g) at a certain temperature and total 2 at...One mole of N2O4 (g) at 300 K is kept in a closed container under one atm. It is heated to 600 K when 20% by mass of N2O...For the gaseous reaction: CO + H2O$\rightleftharpoons$CO2 + H2, the following thermodynamical data are given.ΔHo300 K = ...From the following data, (i) H2(g) + CO2(g) $\rightleftharpoons$ H2O(g) + CO(g); K2000 K = 4.4(ii) 2H2O(g) $\rightleftha...At a certain temperature, the value of KP for the reaction: 2CO(g) $\rightleftharpoons$CO2(g) + C(graphite) is 0.1 atm−1...