Chemical EquilibriumHard

Question

In a system A(s) $\rightleftharpoons$2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor of 2, then it will cause the equilibrium concentration of B to decrease by

Options

A.two times the original value
B.one half of its original value
C.$2\sqrt{2}$times its original value
D.8 times its original value

Solution

K = [B]2 [C]3 = Constant

Now, $\lbrack B\rbrack^{2}\lbrack C\rbrack^{3} = \lbrack B\rbrack_{new}^{2} \times \left( 2\lbrack C\rbrack \right)^{3} \Rightarrow \lbrack B\rbrack_{new} = \frac{\lbrack B\rbrack}{2\sqrt{2}}$

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