Chemical EquilibriumMedium

Question

In a system A(s) $\rightleftharpoons$2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor of 2, then it will cause the equilibrium concentration of B to decrease by

Options

A.two times the original value
B.one half of its original value
C.$2\sqrt{2}$times its original value
D.8 times its original value

Solution

K = [B]2 [C]3 = Constant

Now, $\lbrack B\rbrack^{2}\lbrack C\rbrack^{3} = \lbrack B\rbrack_{new}^{2} \times \left( 2\lbrack C\rbrack \right)^{3} \Rightarrow \lbrack B\rbrack_{new} = \frac{\lbrack B\rbrack}{2\sqrt{2}}$

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

The equilibrium constant for the reaction N2(g) + O2(g) $\rightleftharpoons$ 2NO(g) is K1 and the equilibrium constant f...For the equilibrium LiCl·3NH3(s) $\rightleftharpoons$LiCl·NH3(s) + 2NH3(g); KP = 9 atm2 at 27°C. A 8.21 L vessel contain...At $T(K)$, the equilibrium constant of$A_{2}(\text{ }g) + B_{2}(\text{ }g) \rightleftharpoons C(g)$ is $2.7 \times 10^{-...An equilibrium mixture in a vessel of capacity 100 litre contain 1 mol N2, 2 mol O2 and 3 mol NO. Number of moles of O2 ...Which one of the following has lowest melting point :-...