Chemical EquilibriumHard

Question

In a system A(s) $\rightleftharpoons$2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor of 2, then it will cause the equilibrium concentration of B to decrease by

Options

A.two times the original value
B.one half of its original value
C.$2\sqrt{2}$times its original value
D.8 times its original value

Solution

K = [B]2 [C]3 = Constant

Now, $\lbrack B\rbrack^{2}\lbrack C\rbrack^{3} = \lbrack B\rbrack_{new}^{2} \times \left( 2\lbrack C\rbrack \right)^{3} \Rightarrow \lbrack B\rbrack_{new} = \frac{\lbrack B\rbrack}{2\sqrt{2}}$

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

The system PCl5(g) ⇋ PCl3(g) + Cl2(g) attains equilibrium. If the equilibrium cocentrateion of PCl3(g) is doubled,...The reaction ZnO(s) + CO(g) $\rightleftharpoons$Zn(g) + CO2(g) has an equilibrium constant of 1 atm at 1500 K. The equil...Under what pressure must an equimolar mixture of Cl2 and PCl3 be placed at 250oC in order to obtain 75% conversion of PC...Starting with 2 moles of SO2 and 1 mol of O2 in 1 L flask, the equilibrium mixture required 0.4 moles of MnO4– for compl...The position of equilibrium will shift in the given direction by the addition of inert gas at constant pressure in which...