Chemical EquilibriumMedium
Question
In a 5.76 L vessel, 0.5 moles of H2 gas and 0.5 moles of I2 vapours are allowed to react to form HI (g) at 447°C, then the total pressure of gases at equilibrium would be (R = 0.08 L-atm/K-mol)
Options
A.20 atm
B.10 atm
C.5 atm
D.1 atm
Solution
H2(g) + I2(g) $\rightleftharpoons$ 2HI(g)
As Δng = 0, moles of system is not changing.
$P = \frac{nRT}{V} = \frac{(0.5 + 0.5) \times 0.08 \times 720}{5.76} = 10\text{ atm}$
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