Chemical EquilibriumMedium
Question
XeF6 + H2O $\rightleftharpoons$ XeOF4 + 2HF; equilibrium constant = K1.
XeO4 + XeF6 $\rightleftharpoons$ XeOF4 + XeO3F2; equilibrium constant = K2.
The equilibrium constant for the following reaction will be: XeO4 + 2HF $\rightleftharpoons$ XeO3F2 + H2O
Options
A.$\frac{K_{1}}{K_{2}}$
B.K1 + K2
C.$\frac{K_{2}}{K_{1}}$
D.K2 – K1
Solution
Required reaction may be obtained by subtracting the first reaction from second and hence, $K = \frac{K_{2}}{K_{1}}$.
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