Chemical EquilibriumHard
Question
XeF6 + H2O $\rightleftharpoons$ XeOF4 + 2HF; equilibrium constant = K1.
XeO4 + XeF6 $\rightleftharpoons$ XeOF4 + XeO3F2; equilibrium constant = K2.
The equilibrium constant for the following reaction will be: XeO4 + 2HF $\rightleftharpoons$ XeO3F2 + H2O
Options
A.$\frac{K_{1}}{K_{2}}$
B.K1 + K2
C.$\frac{K_{2}}{K_{1}}$
D.K2 – K1
Solution
Required reaction may be obtained by subtracting the first reaction from second and hence, $K = \frac{K_{2}}{K_{1}}$.
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
For the given reaction at constant pressure, n A (g) ⇋ An (g)Initial moles 1 0Moles at equilibrium 1 - α ^...For the reaction NH2COONH4(s) $\rightleftharpoons$2NH3(g) + CO2(g), KP = 3.2 × 10−5 atm3. The total pressure of the gase...The equilibrium N2 (g) + O2 (g) ⇋ 2NO (g) is estabilished in a reaction vessel of 2.5 L capacity. The amounts of N...The degree of dissociation of SO3 is α at equilibrium pressure P0. Kp for 2SO3(g) ⇋ 2SO2(g) + O2(g) is...An amount of 1 mole each of A and D is introduced in 1 L container. Simultaneously the following two equilibria are esta...