The specific heat of a metal is found to be 0.03. 10 g of the metal on treatment with nitric acid ga

Question

The specific heat of a metal is found to be 0.03. 10 g of the metal on treatment with nitric acid gave 18.9 g of pure dry nitrate. The correct statement(s) is/are

Accepted Answer

Atomic weight (approx.) $\frac{6.4}{0.03} = 213.33$

Now, $\frac{10}{E_{M}} = \frac{18.9}{E_{M} + 62} \Rightarrow E_{M} = 69.66$

Now, Valency $\approx \frac{213.33}{69.6} \approx 3$ (Integer value)

∴ Atomic weight (exactly) = $69.66 \times 3 = 208.98$

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