Redox and Equivalent ConceptHard
Question
A certain amount of a reducing agent reduces x mole of MnO2 and y mole of K2CrO4 in different reactions in acidic medium. If the changes in oxidation states of reducing agent in the reactions are in 1: 2 ratio, respectively, then the ratio of x and y is
Options
A.2:3
B.1:3
C.3:4
D.3:2
Solution
$n_{eq}R.A. = n_{eq}MnO_{2} \Rightarrow n \times 1 = x \times 2\text{and }n_{eq}R.A. = n_{eq}K_{2}CrO_{4} \Rightarrow n \times 2 = y \times 3$
$\therefore x:y = 3:4$
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