Redox and Equivalent ConceptHard
Question
A metal forms two oxides. The higher oxide contains 20% oxygen, while 4.29 g of the lower oxide when converted to higher oxide, become 4.77 g. The equivalent weight of metal in
Options
A.lower oxide is 32.
B.lower oxide is 64.4.
C.higher oxide is 64.4.
D.higher oxide is 32.
Solution
Higher oxide: $\frac{80}{E_{M}} = \frac{20}{8} \Rightarrow E_{M} = 32$
Lower oxide (4.29 g) → Higher oxide (4.77 g)
Mass of metal = $4.77 \times \frac{80}{100} = 3.816\text{ g}$
Mass of oxygen = 4.29 – 3.816 = 0.474 g
Lower oxide: $\frac{3.816}{E_{M}} = \frac{0.474}{8} \Rightarrow E_{M} = 64.4$
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