A metal forms two oxides. The higher oxide contains 20% oxygen, while 4.29 g of the lower oxide when

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A metal forms two oxides. The higher oxide contains 20% oxygen, while 4.29 g of the lower oxide when converted to higher oxide, become 4.77 g. The equivalent weight of metal in

Accepted Answer

Higher oxide: $\frac{80}{E_{M}} = \frac{20}{8} \Rightarrow E_{M} = 32$

Lower oxide (4.29 g) → Higher oxide (4.77 g)

Mass of metal = $4.77 \times \frac{80}{100} = 3.816\text{ g}$

Mass of oxygen = 4.29 – 3.816 = 0.474 g

Lower oxide: $\frac{3.816}{E_{M}} = \frac{0.474}{8} \Rightarrow E_{M} = 64.4$

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