Redox and Equivalent ConceptHard

Question

A volume of 100 ml of 0.1 M-NaAl(OH)2CO3 is neutralized by 0.25 N-HCl to form NaCl, AlCl3 and CO2. The volume of HCl required is

Options

A.10 ml
B.40 ml
C.100 ml
D.160 ml

Solution

$NaAl(OH)_{2}CO_{3} + 4HCl \rightarrow NaCl + AlCl_{3} + CO_{2} + 3H_{2}O$

$n_{eq}NaAl(OH)_{2}CO_{3} = n_{eq}HCl $$$\text{Or }\frac{100 \times 0.1}{1000} \times 4 = \frac{V \times 0.25}{1000} \Rightarrow V = 160\text{ ml}$$

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