Redox and Equivalent ConceptHard
Question
In the reaction, Pb + PbO2 + H2SO4 → PbSO4 + H2O, the equivalent weight of H2SO4 is
Options
A.M
B.M/2
C.2M
D.M/4
Solution
$Pb + PbO_{2} + 2H_{2}SO_{4} \rightarrow 2PbSO_{4} + 2H_{2}O$
The reaction is balanced by the loss and gain of 2 moles of electron per mole of Pb and hence, $E_{H_{2}SO_{4}} = \frac{2M}{2} = M$
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