Redox and Equivalent ConceptHard
Question
A quantity of 1 g of metal ion, M2+ was discharged by the passage of 1.81 × 1022 electrons. The atomic mass of the metal is
Options
A.33.27
B.99.81
C.66.54
D.133.08
Solution
$\underset{A\text{ gm}}{M^{2 +}} + \underset{2N_{A}e^{-}}{2e^{-}} \rightarrow M$
$\therefore 1g \rightarrow \frac{2N_{A}}{A} \times 1 = 1.81 \times 10^{22} \Rightarrow A = 66.54$
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