Redox and Equivalent ConceptMedium
Question
An oxide, X2O3 is oxidized to XO4− by Cr2O72− in acid medium. The number of moles of X2O3 oxidized per mole of Cr2O72− is
Options
A.3/4
B.3
C.3/2
D.2/3
Solution
$3X_{2}O_{3} + 4Cr_{2}O_{7}^{2 -} + 26H^{+} \rightarrow 6XO_{4}^{-} + 8Cr^{3 +} + 13H_{2}O$
Method II: (After equivalent concept)
$n_{eq}\text{of }\text{X}_{2}O_{3} = n_{eq}Cr_{2}O_{7}^{2 -}$
Or, $n \times 8 = 1 \times 6 \Rightarrow n_{x_{2}O_{3}} = \frac{3}{4}$
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