Mole ConceptHard
Question
A quantity of 8 g CH4 is mixed with 28 g O2 and fired. Which of the following is correct about the combustion of CH4 in this condition?
Options
A.1 g CH4 will remain left unburned if carbon is quantitatively converted into CO2.
B.4 g O2 will remain unused if carbon is quantitatively converted into CO.
C.Equal moles of CO and CO2 are formed if none of the reactants is left and there is no other side reaction.
D.18 g water will form in any possible condition.
Solution
(a) CH4 + 2O2 → CO2 + 2H2O
16 g 64 g
7 g ← 28 g
(b) CH4 + 3/2 O2 → CO + 2H2O
16 g 48 g
∴ 8 g 24 g
$(c),(d)\frac{1}{2}CH_{4} + \frac{7}{8}O_{2} \rightarrow \frac{1}{4}CO_{2} + \frac{1}{4}CO + \underset{18\text{ g}}{H_{2}O}$
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