Mole ConceptHard
Question
A quantity of 8 g CH4 is mixed with 28 g O2 and fired. Which of the following is correct about the combustion of CH4 in this condition?
Options
A.1 g CH4 will remain left unburned if carbon is quantitatively converted into CO2.
B.4 g O2 will remain unused if carbon is quantitatively converted into CO.
C.Equal moles of CO and CO2 are formed if none of the reactants is left and there is no other side reaction.
D.18 g water will form in any possible condition.
Solution
(a) CH4 + 2O2 → CO2 + 2H2O
16 g 64 g
7 g ← 28 g
(b) CH4 + 3/2 O2 → CO + 2H2O
16 g 48 g
∴ 8 g 24 g
$(c),(d)\frac{1}{2}CH_{4} + \frac{7}{8}O_{2} \rightarrow \frac{1}{4}CO_{2} + \frac{1}{4}CO + \underset{18\text{ g}}{H_{2}O}$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
A mixture is made equal volume of CO and air. A spark passed through so that all the oxygen is converted to carbon dioxi...An unknown oxide of manganese is reacted with carbon to form manganese metal and CO2. Exactly 31.6 g of the oxide, MnxOy...A compound contains equal masses of the elements A, B and C. If the atomic masses of A, B and C are 20, 40 and 60, respe...For CuSO4·5H2O, which is the correct mole relationship?...16 g of an ideal gas SOx occupies 5.6 L. at STP. The value of x is...