Mole ConceptHard
Question
A volume of 20 ml of 8.5% (w/v) H2O2 solution is diluted to 50 ml. A volume of 10 ml of the diluted solution is reacted with excess of an oxidant. It will cause liberation of ___ ml of ___ gas at 0o C and 1 atm.
Options
A.56, O2
B.112, O2
C.224, H2
D.224, H2
Solution
Mass of H2O2 in 10 mL diluted solution $= \frac{1}{5} \times \left( 20 \times \frac{8.5}{100} \right) = \frac{8.5}{25}\text{ g}$
As 1 mole of H2O2 will produce 1 mole of O2 on reaction with the oxidant, volume of O2 gas produced at 0°C and 1 atm $= \frac{8.5/25}{34} \times 22400 = 224\text{ mL}$
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