Mole ConceptHard
Question
A metal oxide has the formula M2O3. It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide required 6 mg of hydrogen for complete reduction. The atomic mass of the metal is
Options
A.111.60
B.159.60
C.79.80
D.55.80
Solution
$M_{2}O_{3} + 3H_{2} \rightarrow 2M + 3H_{2}O$
(2A + 48)g 6 g
$\therefore 0.1596\text{ g}\frac{6}{2A + 48} \times 0.1596 = 6 \times 10^{- 3}$
⇒ A = 55.8.
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