Mole ConceptHard
Question
A quantity of 500 g of an aq. urea solution having mole fraction of solute, 0.2 is diluted to 1500 g. The mole fraction of solute in the diluted solution is
Options
A.0.05
B.0.067
C.0.6
D.0.1
Solution
$0.2 \times \left( \frac{50}{0.2 \times 60 + 0.8 \times 18} \right) = x \times \left( \frac{1500}{x \times 60 + (1 - x) \times 18} \right) \Rightarrow x = 0.0508$
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