Mole ConceptHard

Question

What total volume, in litre at 727oC and 1 atm, could be formed by the decomposition of 16 g of NH4NO3? Reaction: 2NH4NO3 → 2N2 + O2 + 4H2O(g).

Options

A.57.47 L
B.114.94 ml
C.41.78 L
D.24.63 L

Solution

2NH4NO3 → 2N2 + O2 + 4H2O(g)

2 × 80 g Total 7 mole gases

∴16 g 0.7 mole

∴ Volume, $V = \frac{0.7 \times 0.082 \times 900}{1} = 57.4\text{ L}$

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