When a sample of hydrogen fluoride is cooled to 303 K, most of the molecules undergo dimerization. I

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When a sample of hydrogen fluoride is cooled to 303 K, most of the molecules undergo dimerization. If the vapour density of such a sample is 18, then what per cent of total molecules in the sample are in dimer form? (F = 19)

Accepted Answer

$\alpha = \frac{M_{o} - M}{(n - 1).M} = \frac{20 - 36}{\left( \frac{1}{2} - 1 \right) \times 36} = \frac{8}{9}$

∴ Percentage of total molecules in dimer form = $\frac{\alpha/2}{1 - \frac{\alpha}{2}} \times 100 = 80\%$

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