Mole ConceptMedium
Question
The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. The volume of CO2 produced when 100 ml of the mixture is burnt in excess of O2 is
Options
A.153 ml
B.173 ml
C.193 ml
D.213 ml
Solution
Volume of CO2 formed = 3 × 36.5 + (100 − 36.5) = 173 mL
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