Mole ConceptHard
Question
The volume of one mole of water at 277 K is 18 ml. One ml of water contains 20 drops. The number of molecules in one drop of water will be (NA = 6 × 1023)
Options
A.1.07 × 1021
B.1.67 × 1021
C.2.67 × 1021
D.1.67 × 1020
Solution
Volume of 18 g of water is 18 mL. Hence, the mass of one drop of water =$\frac{1}{20}$= 0.05 g.
Number of water molecules in one drop $= \frac{0.05}{18} \times 6 \times 10^{23} = 1.67 \times 10^{21}$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
A quantity of 2.76 g of silver carbonate on being strongly heated yields a residue weighing (Ag = 108)...A quantity of 1 g of metallic carbonate XCO3 is completely converted into a chloride XCl2 weighing 1.11 g. The atomic ma...Diborane tetrachloride was treated with NaOH and the following reaction occurred.B2Cl4 + NaOH → NaBO2 + H2O + H2 + NaClI...In a compound C, H and N atoms are present in 9 : 1 : 35 by weight. Molecular weight of compound is 108. Molecular formu...2. 76 g of silver carbonate on being strongly heated yields a residue weighing :...