Mole ConceptMedium
Question
The volume of one mole of water at 277 K is 18 ml. One ml of water contains 20 drops. The number of molecules in one drop of water will be (NA = 6 × 1023)
Options
A.1.07 × 1021
B.1.67 × 1021
C.2.67 × 1021
D.1.67 × 1020
Solution
Volume of 18 g of water is 18 mL. Hence, the mass of one drop of water =$\frac{1}{20}$= 0.05 g.
Number of water molecules in one drop $= \frac{0.05}{18} \times 6 \times 10^{23} = 1.67 \times 10^{21}$
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