Mole ConceptHard
Question
The mass of 3.2 × 105 atoms of an element is 8.0 × 10−18 g. The atomic mass of the element is about
(NA = 6 × 1023)
Options
A.2.5 × 10−22
B.15
C.8.0 × 10−18
D.30
Solution
Atomic mass of the element = $\frac{8.0 \times 10^{- 18}}{3.2 \times 10^{5}} \times 6 \times 10^{23} = 15$
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