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Question

Consider the following reactions.

$${PbCl}_{2} + K_{2}{CrO}_{4} \rightarrow \text{ }A + 2KCl $$(Hot solution)

$${A + NaOH \rightleftharpoons B + {Na}_{2}{CrO}_{4} }{{PbSO}_{4} + 4{CH}_{3}{COONH}_{4} \rightarrow \left( {NH}_{4} \right)_{2}{SO}_{4} + X }$$In the above reactions, $A,B$ and X are respectively.

Options

A.${Na}_{2}\left\lbrack \text{ }Pb(OH)_{2} \right\rbrack,{PbCrO}_{4}$ and $\left( {NH}_{4} \right)_{2}\left\lbrack \text{ }Pb\left( {CH}_{3}COO \right)_{4} \right\rbrack$
B.${PbCrO}_{4},{Na}_{2}\left\lbrack \text{ }Pb(OH)_{4} \right\rbrack$ and $\left\lbrack Pb\left( {NH}_{3} \right)_{4} \right\rbrack{SO}_{4}$
C.${Na}_{2}\left\lbrack \text{ }Pb(OH)_{2} \right\rbrack,{PbCrO}_{4}$ and $\left\lbrack Pb\left( {NH}_{3} \right)_{4} \right\rbrack{SO}_{4}$
D.${PbCrO}_{4},{Na}_{2}\left\lbrack \text{ }Pb(OH)_{4} \right\rbrack$ and $\left( {NH}_{4} \right)_{2}\left\lbrack \text{ }Pb\left( {CH}_{3}COO \right)_{4} \right\rbrack$

Solution

$\underset{\text{~(Hot solution)~}}{{PbCl}_{2}} + K_{2}{CrO}_{4} \rightarrow \underset{\text{~(A)~}}{{PbCrO}_{4}} + 2KCl$

${PbCrO}_{4} + 4NaOH$ (excess)$\rightarrow {Na}_{2}\left\lbrack \text{ }Pb(OH)_{4} \right\rbrack + {Na}_{2}{CrO}_{4}$

$$\begin{matrix} {PbSO}_{4} & \ + 4{CH}_{3}{COONH}_{4} \\ & \ \rightarrow \left( {NH}_{4} \right)_{2}\left\lbrack \text{ }Pb\left( \underset{(X)}{\left( {CH}_{3}COO \right)_{4}} \right\rbrack + \left( {NH}_{4} \right)_{2}{SO}_{4} \right.\ \end{matrix}$$

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