Atomic StructureEasy
Question
The orbital angular momentum of an electron is 2s orbital is
Options
A.$+ \frac{1}{2}.\frac{h}{2\pi}$
B.0
C.$\frac{h}{2\pi}$
D.$\sqrt{2}\frac{h}{2\pi}$
Solution
Orbital angular momentum $= \sqrt{l(l + 1)}.\frac{h}{2\pi}$ and for s-orbital, l = 0.
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