Atomic StructureEasy

Question

The amount of energy released when an electron jumps from the seventh excited state to the first excited state in He+ ion is

Options

A.13.32 eV
B.53.28 eV
C.12.75 eV
D.26.08 eV

Solution

$\Delta E = 13.6z^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)eV = 13.6 \times 2^{2}\left( \frac{1}{2^{2}} - \frac{1}{8^{2}} \right) = 12.75\text{ eV}$

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