The amount of energy released when an electron jumps from the seventh excited state to the first exc

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The amount of energy released when an electron jumps from the seventh excited state to the first excited state in He+ ion is

Accepted Answer

$\Delta E = 13.6z^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} ight)eV = 13.6 	imes 2^{2}\left( \frac{1}{2^{2}} - \frac{1}{8^{2}} ight) = 12.75	ext{ eV}$

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