Atomic StructureHard
Question
In H-atom, the wave number ratio is 108: 7 is for
Options
A.first Lyman and first Balmer transition.
B.first Lyman and first Brackett transition.
C.first Lyman and first Paschen transition.
D.first Lyman and second Balmer transition.
Solution
$\frac{\lambda_{2}}{\lambda_{1}} = \frac{\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)_{1}}{\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)_{2}} = \frac{\left( \frac{1}{1^{2}} - \frac{1}{2^{2}} \right)}{\left( \frac{1}{3^{2}} - \frac{1}{4^{2}} \right)} = \frac{108}{7}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The number of nodal planes in a Px orbotal is :...Wave number of the first line in the Balmer series of Be3+ is 2.5 × 105 cm−1. Wave number of the second line of the Pasc...The distance of closest approach of an α-particle fired towards a nucleus with momentum ‘P’ is r. What will be the dista...According to Bohr′s theory, the angular momentum of an electron in 5th orbit is...The escape velocity for earth is 11.2 km/s. The orbit number for H-atom in which speed of electron is about 19.54 times ...