Atomic StructureEasy
Question
What is the frequency of the second line of the Paschen series in the spectrum of He+ ion?
Options
A.$\frac{64RC}{225}$
B.$\frac{64R}{225}$
C.$\frac{225}{64R}$
D.$\frac{225C}{64R}$
Solution
Second line of Panchen series is 5 → 3.
Now, $\upsilon = \frac{c}{\lambda} = CRz^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right) = CR \times 2^{2}\left( \frac{1}{3^{2}} - \frac{1}{5^{2}} \right) = \frac{64CR}{225}$
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