Atomic StructureEasy
Question
The ionization energy of a hypothetical atom is 50 eV. If this atom obeys Bohr’s atomic model, the energy of electron in its fifth orbit will be
Options
A.–1250 eV
B.+ 2 eV
C.–2 eV
D.+1250 eV
Solution
$E_{1} = - I.E. = - 50\text{ eV}$
Now, $E_{n} = \frac{E_{1}}{n^{2}} \Rightarrow E_{5} = \frac{- 50}{5^{2}} = - 2\text{ eV}$
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