Atomic StructureHard
Question
As the orbit number increases, the K.E. and P.E. for an electron
Options
A.both increases.
B.both decreases.
C.K.E. increases but P.E. decreases.
D.P.E. increases but K.E. decreases.
Solution
$K.E. = \frac{1}{2}mv^{2},P.E. = - mv^{2}\text{ and }V \propto \frac{1}{n}$
Therefore, with increase in orbit number, K.E. decreased but P.E. increases.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The speed of electron revolving around H-nucleus is 0.547 × 106 m/s. The distance of electron from the nucleus is...After np orbitals are filled, the next orbital filled will be :...Identify the INCORRECT statements from the following:A. Notation $\ _{12}^{24}Mg$ represents 24 protons and 12 neutrons....The number of radial nodes of 3s, 3p and 3d electrons are, respectively,...The orbital angular momentum of a p-electron is given as:...