Atomic StructureEasy
Question
What is the angular speed of an electron revolving in the third orbit of He+ ion?
Options
A.6.12 × 1015 s−1
B.1.63 × 10–16 s
C.1.92 × 1016 s–1
D.1.95 × 1015 s–1
Solution
$w = \frac{V}{r} = \frac{2.188 \times 10^{6} \times \frac{2}{3}}{0.529 \times 10^{- 10} \times \frac{3^{2}}{2}} = 6.13 \times 10^{15}s^{- 1}$
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