Atomic StructureEasy
Question
The ratio of circumference of third and second orbits of He+ ion is
Options
A.3: 2
B.2: 3
C.9: 4
D.4: 9
Solution
$\frac{(2\pi r)_{3}}{(2\pi r)_{2}} = \frac{3^{2}}{2^{2}} = \frac{9}{4}$
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