Atomic StructureEasy
Question
The I.P. of an atom is 16 eV. What is the value of first excitation potential :-
Options
A.10.2 eV
B.12 eV
C.14 eV
D.16 eV
Solution
E∞ - E1 = 16 eV ⇒ E1 = -16 eV
E2 =
= - 4 eV
Ist excitation potential = E2 - E1
= - 4 eV - (-16 eV) = 12 eV
E2 =
= - 4 eVIst excitation potential = E2 - E1
= - 4 eV - (-16 eV) = 12 eV
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