Atomic StructureEasy
Question
According to Bohr's model, the radius of Ne9+ ion in ground state should be
Options
A.0.529 Å
B.0.0529 Å
C.5.29 Å
D.52.9 Å
Solution
$r_{1,Ne^{+ 9}} = 0.529 \times \frac{1^{2}}{10} = 0.0529\overset{0}{A}$
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