Atomic StructureHard
Question
A photo sensitive surface is receiving light of wavelength 5000 Å at the rate of 10−7 J/s. The number of photons received per second is
a) 2.5 × 1011 (b) 3.0 × 1032 (c) 2.5 × 1018 (d) 2.5 × 109
Solution
$E = n.\frac{hc}{\lambda} \Rightarrow \frac{E.\lambda}{hc} = \frac{10^{- 7} \times 5000 \times 10^{- 10}}{6.626 \times 10^{- 34} \times 3 \times 10^{8}} = 2.5 \times 10^{11}$
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