Atomic StructureHard

Question

A photo sensitive surface is receiving light of wavelength 5000 Å at the rate of 10−7 J/s. The number of photons received per second is

a) 2.5 × 1011 (b) 3.0 × 1032 (c) 2.5 × 1018 (d) 2.5 × 109

Solution

$E = n.\frac{hc}{\lambda} \Rightarrow \frac{E.\lambda}{hc} = \frac{10^{- 7} \times 5000 \times 10^{- 10}}{6.626 \times 10^{- 34} \times 3 \times 10^{8}} = 2.5 \times 10^{11}$

Create a free account to view solution

View Solution Free
Topic: Atomic Structure·Practice all Atomic Structure questions

More Atomic Structure Questions

Among the following, the correct statement(s) is(are)...Mny elements have non-integral atomic masses because :...How many nodal spheres are present in 4s - orbital:-...A dye emits 50% of the absorbed energy as fluorescence. If the number of quanta absorbed and emitted out is in the ratio...For principle quantum number n = 4, the total number of orbitals having l = 3 is :...