Atomic StructureEasy

Question

The eyes of a certain member of the reptile family pass a single visual single to the brain when the visual receptors are stuck by photons of wavelength 662.6 nm. If a total energy of 3.0 × 10–14 J is required to trap the signal, what is the minimum number of photons that must strike the receptor?

Options

A.1.0 × 105
B.1.0 × 106
C.1000
D.1

Solution

$E = n.\frac{hc}{\lambda} \Rightarrow n = \frac{E.\lambda}{hc} = \frac{\left( 3 \times 10^{- 14} \right) \times \left( 662.6 \times 10^{- 9} \right)}{\left( 6.626t10^{- 34} \right) \times \left( 3 \times 10^{8} \right)} = 10^{5}$

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