Atomic StructureHard
Question
In presence of HCl, metallic tin (Sn) is oxidised into stannic chloride with the help of K2Cr2O7. How many mL of 0.1 N K2Cr2O7 will be required for the oxidation of 1 gm of tin (Atomic mass of Sn = 118.7)
Options
A.226.98
B.336.98
C.405.86
D.306.98
Solution
The redox Reaction is as follows
Sn → Sn4+ + 4e-
Cr2O72- + 6e- → 2Cr3+
gmeq. of Sn = gmeq. of K2Cr2O7
= N × V(l)
= 0.1 × V(L)
Sn → Sn4+ + 4e-
Cr2O72- + 6e- → 2Cr3+
gmeq. of Sn = gmeq. of K2Cr2O7
= N × V(l) = 0.1 × V(L)Create a free account to view solution
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