Atomic StructureHard

Question

Two particles A and B having same e/m ratio are projected towards silver nucleus in di­fferent experiments with the same speed. The distance of closest approach will be

Options

A.same for both.
B.greater for A.
C.greater for B.
D.depends on speed.

Solution

$r = \frac{K.q_{1}q_{2}}{\left( \frac{1}{2}mv^{2} \right)}$

As $\left( \frac{q_{1}}{m} \right)$, q2 and v, all are same, r is same.

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