Atomic StructureEasy
Question
An α-particle accelerated through V volt is fired towards a nucleus. The distance of closest approach is r. If a proton accelerated through the same potential is fired towards the same nucleus, the distance of closest approach of the proton will be
Options
A.r
B.2r
C.r/2
D.r/4
Solution
$r = K.\frac{q_{1}q_{2}}{q_{1}.V} = \text{Constant}$
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