Atomic StructureEasy
Question
The potential difference between cathode and anode in a cathode ray tube is V. The speed acquired by the electrons is proportional to
Options
A.V
B.$\sqrt{V}$
C.V2
D.$1/\sqrt{V}$
Solution
$e.V. = \frac{1}{2}mv^{2} \Rightarrow v = \sqrt{2 \times \left( \frac{e}{m} \right) \times V}\alpha\sqrt{V}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The excitation energy of an electron from second orbit to third orbit of a hydrogen-like atom or ion with +Ze nuclear ch...For the Hydrogen spectrum, last line of the Lyman series has frequency v1, last line of Lymen series of He+ ion has freq...The quantum numbers +1/2 and –1/2 for the electron spin represent...The e/m ratio of a particle of charge 2 unit and mass 4 amu is...The value of the magnetic moment of a particular ion is 2.83 Bohr magneton. The ion is -...