Atomic StructureHard
Question
For an electron in a hydrogen atom, the wave function is given by $\Psi_{1s} = \left( \pi/\sqrt{2} \right)e^{- r/a_{0}}$, where ao is the radius of first Bohr’s orbit and r is the distance from the nucleus with which the probability of finding electron varies. What will be the ratio of probabilities of finding electrons at the nucleus to first Bohr’s orbit ao?
Options
A.0
B.e
C.$e^{2}$
D.$\frac{1}{e^{2}}$
Solution
Probability of finding electron at the nucleus = 0
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