Atomic StructureHard
Question
For an electron in a hydrogen atom, the wave function is given by $\Psi_{1s} = \left( \pi/\sqrt{2} \right)e^{- r/a_{0}}$, where ao is the radius of first Bohr’s orbit and r is the distance from the nucleus with which the probability of finding electron varies. What will be the ratio of probabilities of finding electrons at the nucleus to first Bohr’s orbit ao?
Options
A.0
B.e
C.$e^{2}$
D.$\frac{1}{e^{2}}$
Solution
Probability of finding electron at the nucleus = 0
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Which of the following is paramagnetic?...If e = 1.60206 × 10-19 C, = 1.75875 × 1011C kg-1then mass of electron is...If λ be the de Broglie wavelength of a thermal neutron at 27°C, then the wavelength of the same neutron at 927°C is...An electron and a proton are accelerated through a potential V. If Pe and Pp are their momentum, then PP: Pe ratio is ap...The wavelength of a spectral line obtained by an electronic transition is inversely proportional to...