Atomic StructureHard
Question
The frequency of an electromagnetic radiation which makes 2 × 106 waves per 50 cm is
Options
A.1.2 × 1015 Hz
B.150 Hz
C.6 × 1014 Hz
D.1.2 × 1013 Hz
Solution
$\upsilon = c\bar{\upsilon} = \left( 3 \times 10^{10}\text{ cm/s} \right) \times \left( \frac{2 \times 10^{6}}{50}\text{c}\text{m}^{- 1} \right) = 1.2 \times 10^{15}\text{ Hz}$
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