Atomic StructureHard
Question
A proton and an α-particle are accelerated through the same potential difference. The ratio of their de Broglie wavelengths is
Options
A.1: 1
B.2: 1
C.$\sqrt{2}$: 1
D.2$\sqrt{2}$: 1
Solution
$\lambda = \frac{h}{\sqrt{2mE}} \Rightarrow \frac{\lambda_{p}}{\lambda_{\alpha}} = \sqrt{\frac{4 \times 2}{1 \times 1}} = \frac{2\sqrt{2}}{1}$
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