Atomic StructureHard
Question
A certain molecule has an energy level diagram for its vibrational energy in which two levels are 0.0141 eV apart. The wavelength of the emitted line for the molecule as it falls from one of these levels to the other is about
Options
A.88 μm
B.88 mm
C.174.84 m
D.88 nm
Solution
$\lambda = \frac{1240}{0.0141} = 8.8 \times 10^{4}\text{ nm = 8.8} \times \text{1}\text{0}^{- 5}\text{m = 88 nm}$
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