Atomic StructureHard

Question

A lithium atom has three electrons. Assume the following simple picture of the atom. Two electrons move close to the nucleus making up a spherical cloud around it and the third moves outside this cloud in a circular orbit. Bohr’s model can be used for the motion of this third electron but n = 1 state is not available to it. The ionization energy of lithium in ground state, using the above picture, is

Options

A.13.6 eV
B.10.2 eV
C.3.4 eV
D.1.51 eV

Solution

n = 2 but z = 3 – 2 =1

$\therefore E_{2} = - 13.6 \times \frac{1^{2}}{2^{2}} = - 3.4\text{ eV}$

and I.E. = 3.4 eV

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