The ionization energy of a hydrogen-like atom is 14.4 eV. The amount of energy released when electro

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The ionization energy of a hydrogen-like atom is 14.4 eV. The amount of energy released when electron jumps from the fourth orbit to the first orbit in this atom is

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$\Delta E = \left( 	ext{I.E.} ight)\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} ight) = 14.4 	imes \left( \frac{1}{1^{2}} - \frac{1}{4^{2}} ight) = 13.5	ext{ eV}$

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