Atomic StructureHard
Question
The time period of revolution in the third orbit of Li2+ ion is x second. The time period of revolution in the second orbit of He+ ion should be
Options
A.$x$ s
B.$\frac{3}{2}x$s
C.$\frac{2}{3}x$s
D.$\frac{8}{27}x$s
Solution
$T_{n,z} = 1.5 \times 10^{- 16}\frac{n^{3}}{z^{2}}\text{sec}$
$\frac{T_{2,H_{e}^{+}}}{T_{3,Li^{2 +}}} = \frac{2^{3}/2^{2}}{3^{3}/3^{2}} \Rightarrow T_{2,H_{e}^{+}} = \frac{2}{3}x\text{ sec}$
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