Atomic StructureHard
Question
For which orbit in He+ ion, the circumference is 26.5 Å?
Options
A.2
B.3
C.4
D.16
Solution
$2\pi r_{n} = 26.5\overset{o}{A} \Rightarrow 2\pi \times \text{0.529} \times \frac{n^{2}}{2} = 26.5 \Rightarrow n = 4$
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