Atomic StructureHard

Question

For which orbit in He⁺ ion, the circumference is 26.5 Å?

Options

A.2

B.3

C.4

D.16

Solution

$2\pi r_{n} = 26.5\overset{o}{A} \Rightarrow 2\pi \times \text{0.529} \times \frac{n^{2}}{2} = 26.5 \Rightarrow n = 4$

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