Atomic StructureHard
Question
Which of the following statement is correct?
Options
A.Potassium ferrocyanide can cause greater coagulation in a basic dye as compared to Na2HPO3.
B.A starch aqua sol can act as protective colloid for Fe(OH)3
C.The slope of the Freundlich adsorption isotherm ($\log\frac{x}{m}$ vs. log P) keeps on changing for a long range of pressure and is constant over a limited range of pressure.
D.Higher the zeta potential, greater is the stability of colloid.
Solution
(a) Basic dye is positively charged and hence, $Fe(CN)_{6}^{4 -} > HPO_{3}^{2 -}$
(c) Slope should not change in Freundlich’s isotherm.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The formation of O2-(g) starting from O(g) is endothermic by 639 kJ mol-1 . If electron gain enthalpy of O(g) is –141 kJ..., The compound with the above configuration is named as :-...Last line of Lyman series for H-atom has wavelength λ1, 2nd line of Balmer series has wavelength λ2 Å then...The difference in angular momentum associated with the electron in two successive orbits of hydrogen atom in :-...The orbital having two nodal surfaces is...