Atomic StructureHard
Question
A bulb emits light of wavelength 1987 8 7.nm. The bulb is rated as 200 W and 14% of the energy is emitted as light. How many photons are emitted by the bulb per second?
Options
A.1.2 × 1021
B.4 × 1010
C.1.33 × 1011
D.4 × 1019
Solution
$p = \frac{E}{t} = \frac{n.hc}{t.\lambda}$
$\Rightarrow \frac{14}{100} \times 200 = \frac{n \times 6.626 \times 10^{- 34} \times 3 \times 10^{8}}{1 \times \frac{1987.8}{7} \times 10^{- 9}} $$$\therefore n = 4 \times 10^{19}\text{ }\text{s}^{- 1}$$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The radii of two of the first four Bohr′s orbits of the hydrogen atom are in the ratio 1 : 4 The energy difference...Given below are two statements:Statement I: When an electric discharge is passed through gaseous hydrogen, the hydrogen ...After np orbitals are filled, the next orbital filled will be :...Orbitals used in hybridisation of anion of CsBr3 is:-...Which of the following pairs of compounds is isoelectronic and isostructural ?...