Atomic StructureHard
Question
The mass of a negative meson is 208 time the mass of electron. If the e/m ratio of α-particle is x unit, then the e/m ratio of this meson will be
Options
A.$\frac{x}{208}$unit
B.$\frac{x}{52}$unit
C.17.65 x unit
D.104 x unit
Solution
$\frac{\left( \frac{e}{m} \right)_{\text{mesor}}}{\left( \frac{e}{m} \right)_{\alpha\text{-particle}}} = \frac{\frac{1}{\left( \frac{1}{1836} \times 208 \right)}}{\frac{2}{4}} = \frac{17.65}{1}$
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