Mole ConceptMedium
Question
A volume V of a gaseous hydrocarbon was exploded with an excess of oxygen. The observed contraction was 2.5V, and on treatment with potash, there was a further contraction of 2V. What is the molecular formula of the hydrocarbon?
Options
A.C2H6
B.C3H6
C.C4H12
D.C2H4
Solution
$C_{x}H_{y} + \left( x + \frac{y}{4} \right)O_{2} \rightarrow xCO_{2} + \frac{y}{2}H_{2}O$
$\text{V ml} V\left( x + \frac{y}{4} \right)\text{mL} Vx\text{ mL} 0$
Volume contraction, $\left\lbrack v + v\left( x + \frac{y}{4} \right) \right\rbrack - V_{x} = 2.5V$ and Vx = 2V ⇒ x = 2 and y = 6 ⇒ C2H6
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